Answer by Nik Weaver for Von Neumann Algebras and Measure Theory
Given a localizable measure space $(X,\mu)$, the space $\mathcal{A} = L^\infty(X,\mu)$ is a von Neumann algebra. The integral on $L^\infty(X,\mu)$ is abstractly understood as a weight on $\mathcal{A}$...
View ArticleVon Neumann Algebras and Measure Theory
We know that a abelian von Neumann algebras $\mathcal{A}$ is isomorphic to $\mathscr{L}^{\infty}(X)$ for some special measure space $(X,\Sigma,\mu)$. For that reasone one can see an arbitrary von...
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